2x^2+1120x-10800=0

Solution for 2x^2+1120x-10800=0 equation:

2x^2+1120x-10800=0

a = 2; b = 1120; c = -10800;
Δ = b2-4ac
Δ = 11202-4·2·(-10800)
Δ = 1340800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1340800}=\sqrt{1600*838}=\sqrt{1600}*\sqrt{838}=40\sqrt{838}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1120)-40\sqrt{838}}{2*2}=\frac{-1120-40\sqrt{838}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1120)+40\sqrt{838}}{2*2}=\frac{-1120+40\sqrt{838}}{4}
$